The particle in a box (1-D and 3-D) is probably the
most simple (and buttoned-down, as many students find it) and widely used
example that one can find in any introductory quantum mechanics text. However,
this example can be use to demonstrate some interesting concepts such as
discreetness of energy levels, uncertainty, etc. in quantum mechanics which
students often find difficult to comprehend when encountered in more
complicated systems. I will use the expressions for wave-functions and energy
levels for a particle in a 1-D and 3-D box without going into the drily
derivation part, which can be readily found in any standard QM text.
Discrete energy
levels and quantum numbers: It is important to note here that
the solution of the Schrodinger equation is itself a continuous function. Schrodinger
equation all by itself doesn’t demand the existence of discrete energy levels
or of so called quantum numbers. The discreteness comes into picture when we
try to impose the boundary conditions
on the solution of Schrodinger equation. Boundary conditions arise when there
are boundaries i.e. when we try to confine a particle in a finite region of
space. Thus
It is the confinement that causes discrete energy values.
For example, in case of particle in a 1-D box, the
discreteness comes into picture when we require the wave-function to vanish at
the right boundary i.e. at x = L. Mathematically,
where ‘n’ is called as the ‘quantum number.’
In case of a particle in a 3-D box,
the particle is being confined in three dimensions. This is reflected when we
try to solve the Schrodinger equation and end up with three equations similar
to the Schrodinger equation for a particle in a 1-D box. Again, when we try to
impose the boundary conditions on the solutions of each of these equations, we
get three different quantum numbers, one for each dimension, which quantize the
energy of the particle in a 3-D box. Thus quantum numbers can be regarded as an
indication of the number of dimensions in which the problem is being solved.
If a problem is being solved in
four dimensions we can expect to have four different quantum numbers. For example, trying to solve the Schrodinger
equation (actually it Dirac equation) in 4-D space-time, taking time as the
fourth dimension, we would expect four quantum numbers and that’s exactly what
we get : principle quantum number ‘n’,
orbital quantum number ‘l’, azimuthal
quantum number ‘ml’, and
the fourth quantum number spin ‘s.’
That’s how the spin quantum number comes into picture. These quantum numbers
are given names according to the physical
quantities that they quantize. The name ‘spin’ is, however, the result of
historical misconception. It has nothing to do with the particle actually
spinning.
Uncertainty
:
The idea that the act of observation affects the state of the system is at the
heart of quantum mechanics and forms the content of the so called “Heisenberg’s Uncertainty Principle.”
Mathematically it says,
where Δx and Δp are the “errors” in the measurement
of position and momentum, when measured
simultaneously. These “errors” mathematical jargon are known as standard
deviations, defined in the following manner,
where angular bracets
represent expectation values of x, x2, p and p2. It is instructive to derive the expressions for the standard
deviations in position and momentum. On doing so we get the following result
(for particle in a 1-D box),
It is interesting to note that the
uncertainty product is minimum for the ground state (n = 1). In general, this is true for all the systems – the ground states are minimum uncertainty
states. The uncertainty product
increases as the value of ‘n’
increases i.e. it is higher for higher excited states. But it is always greater
than the minimum value h/4π given by the uncertainty principle . Thus the uncertainty products for different states
in a system are different and are dependent on the values of quantum numbers of
that state. There are systems in which the product turns out to be exactly h/4π
(one such
system is a harmonic oscillator).
An
interesting paradox to think about:
Knowing the energy of the particle
in 1-D box, we can find the expectation value of the square of velocity v2 using the relation E = (1/2)mv2. The energy of
particle in a box is inversely proportional to the length (or volume) of the
box. Hence, as we decrease the length (or volume) of the box, the energy and
the velocity increase. Can we increase the length to such an extent that the
velocity of the particle becomes equal to or greater than the velocity of
light, and hence contradict the theory of relativity? Consider an electron
trapped inside a 1-D box of length L.
Find the length of the box for which the electron’s velocity is equal to the
velocity of the light. Also try to find out the velocity of an electron trapped
inside a nucleus.
As an exercise, try to calculate
the average velocity of a nucleon (a proton or neutron) trapped in a nucleus.
You can approximate the nucleus with a 3-D box of side 1 fermi. Although this
is a very simplistic model of a nucleus – not taking into account the intricate
dynamics of nucleons – the exercise gives an idea of order of magnitude of
velocities of nucleons in nuclei, which are quite huge.
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